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10251420606313 is a prime number
BaseRepresentation
bin1001010100101101100001…
…0010001001111101101001
31100022000201010110101110021
42111023120102021331221
52320424402133400223
633445234305120441
72105432521262365
oct225133022117551
940260633411407
1010251420606313
1132a266a750877
121196964029121
1359492162c263
142762584982a5
1512b9e282265d
hex952d8489f69

10251420606313 has 2 divisors, whose sum is σ = 10251420606314. Its totient is φ = 10251420606312.

The previous prime is 10251420606283. The next prime is 10251420606337. The reversal of 10251420606313 is 31360602415201.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10087179265024 + 164241341289 = 3176032^2 + 405267^2 .

It is a cyclic number.

It is not a de Polignac number, because 10251420606313 - 25 = 10251420606281 is a prime.

It is a super-3 number, since 3×102514206063133 (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (10251420606013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5125710303156 + 5125710303157.

It is an arithmetic number, because the mean of its divisors is an integer number (5125710303157).

Almost surely, 210251420606313 is an apocalyptic number.

It is an amenable number.

10251420606313 is a deficient number, since it is larger than the sum of its proper divisors (1).

10251420606313 is an equidigital number, since it uses as much as digits as its factorization.

10251420606313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 25920, while the sum is 34.

The spelling of 10251420606313 in words is "ten trillion, two hundred fifty-one billion, four hundred twenty million, six hundred six thousand, three hundred thirteen".