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10253011 is a prime number
BaseRepresentation
bin100111000111…
…001011010011
3201021220111011
4213013023103
510111044021
61003431351
7153102106
oct47071323
921256434
1010253011
11587326a
123525557
13217ca92
14150c73d
15d77de1
hex9c72d3

10253011 has 2 divisors, whose sum is σ = 10253012. Its totient is φ = 10253010.

The previous prime is 10252987. The next prime is 10253021. The reversal of 10253011 is 11035201.

It is a strong prime.

It is an emirp because it is prime and its reverse (11035201) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10253011 - 27 = 10252883 is a prime.

It is a super-2 number, since 2×102530112 = 210248469132242, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 10252982 and 10253000.

It is not a weakly prime, because it can be changed into another prime (10253021) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5126505 + 5126506.

It is an arithmetic number, because the mean of its divisors is an integer number (5126506).

Almost surely, 210253011 is an apocalyptic number.

10253011 is a deficient number, since it is larger than the sum of its proper divisors (1).

10253011 is an equidigital number, since it uses as much as digits as its factorization.

10253011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 30, while the sum is 13.

The square root of 10253011 is about 3202.0323233846. The cubic root of 10253011 is about 217.2453425048.

Adding to 10253011 its reverse (11035201), we get a palindrome (21288212).

The spelling of 10253011 in words is "ten million, two hundred fifty-three thousand, eleven".