Base | Representation |
---|---|
bin | 10111010100010110010100… |
… | …111101101101001101000111 |
3 | 111110010000100002121112011011 |
4 | 113110112110331231031013 |
5 | 101420213412413034003 |
6 | 1002040221420423051 |
7 | 30413145452266441 |
oct | 2724262475551507 |
9 | 443100302545134 |
10 | 102553433330503 |
11 | 2a749737609531 |
12 | b6036613a7a87 |
13 | 452b9939907bc |
14 | 1b478811bb491 |
15 | bcc9b43b346d |
hex | 5d4594f6d347 |
102553433330503 has 2 divisors, whose sum is σ = 102553433330504. Its totient is φ = 102553433330502.
The previous prime is 102553433330263. The next prime is 102553433330531. The reversal of 102553433330503 is 305033334355201.
It is a strong prime.
It is an emirp because it is prime and its reverse (305033334355201) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-102553433330503 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (102553433330563) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51276716665251 + 51276716665252.
It is an arithmetic number, because the mean of its divisors is an integer number (51276716665252).
Almost surely, 2102553433330503 is an apocalyptic number.
102553433330503 is a deficient number, since it is larger than the sum of its proper divisors (1).
102553433330503 is an equidigital number, since it uses as much as digits as its factorization.
102553433330503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 729000, while the sum is 40.
Adding to 102553433330503 its reverse (305033334355201), we get a palindrome (407586767685704).
The spelling of 102553433330503 in words is "one hundred two trillion, five hundred fifty-three billion, four hundred thirty-three million, three hundred thirty thousand, five hundred three".
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