Search a number
-
+
102568133 is a prime number
BaseRepresentation
bin1100001110100…
…01000011000101
321011000000000202
412013101003011
5202224140013
614102220245
72353546313
oct607210305
9234000022
10102568133
1152995a58
122a424685
1318332705
14d89d0b3
159010858
hex61d10c5

102568133 has 2 divisors, whose sum is σ = 102568134. Its totient is φ = 102568132.

The previous prime is 102568129. The next prime is 102568177. The reversal of 102568133 is 331865201.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 101263969 + 1304164 = 10063^2 + 1142^2 .

It is a cyclic number.

It is not a de Polignac number, because 102568133 - 22 = 102568129 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 102568096 and 102568105.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (102568933) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51284066 + 51284067.

It is an arithmetic number, because the mean of its divisors is an integer number (51284067).

Almost surely, 2102568133 is an apocalyptic number.

It is an amenable number.

102568133 is a deficient number, since it is larger than the sum of its proper divisors (1).

102568133 is an equidigital number, since it uses as much as digits as its factorization.

102568133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4320, while the sum is 29.

The square root of 102568133 is about 10127.5926557104. The cubic root of 102568133 is about 468.0987522025.

The spelling of 102568133 in words is "one hundred two million, five hundred sixty-eight thousand, one hundred thirty-three".