Base | Representation |
---|---|
bin | 11101111110100100000… |
… | …10110010110000101111 |
3 | 10122110122221110220120022 |
4 | 32333102002302300233 |
5 | 113333440402200221 |
6 | 2105103555312355 |
7 | 134262612105134 |
oct | 16772202626057 |
9 | 3573587426508 |
10 | 1030021131311 |
11 | 367914092217 |
12 | 14775bbab6bb |
13 | 76190b4bc73 |
14 | 37bd35d258b |
15 | 1bbd71664ab |
hex | efd20b2c2f |
1030021131311 has 2 divisors, whose sum is σ = 1030021131312. Its totient is φ = 1030021131310.
The previous prime is 1030021131299. The next prime is 1030021131331. The reversal of 1030021131311 is 1131311200301.
It is a weak prime.
It is an emirp because it is prime and its reverse (1131311200301) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1030021131311 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1030021131311.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1030021131331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515010565655 + 515010565656.
It is an arithmetic number, because the mean of its divisors is an integer number (515010565656).
Almost surely, 21030021131311 is an apocalyptic number.
1030021131311 is a deficient number, since it is larger than the sum of its proper divisors (1).
1030021131311 is an equidigital number, since it uses as much as digits as its factorization.
1030021131311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 1030021131311 its reverse (1131311200301), we get a palindrome (2161332331612).
The spelling of 1030021131311 in words is "one trillion, thirty billion, twenty-one million, one hundred thirty-one thousand, three hundred eleven".
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