Search a number
-
+
103010120027 is a prime number
BaseRepresentation
bin101111111101111100…
…0011011000101011011
3100211212221201021122122
41133323320123011123
53141431042320102
6115153332211455
710304454400433
oct1377370330533
9324787637578
10103010120027
113a760588901
1217b69a69b8b
139938328359
144db2b3d2c3
152a2d62c0a2
hex17fbe1b15b

103010120027 has 2 divisors, whose sum is σ = 103010120028. Its totient is φ = 103010120026.

The previous prime is 103010119943. The next prime is 103010120029. The reversal of 103010120027 is 720021010301.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 103010120027 - 216 = 103010054491 is a prime.

It is a super-2 number, since 2×1030101200272 (a number of 23 digits) contains 22 as substring.

Together with 103010120029, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 103010119987 and 103010120014.

It is not a weakly prime, because it can be changed into another prime (103010120029) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51505060013 + 51505060014.

It is an arithmetic number, because the mean of its divisors is an integer number (51505060014).

Almost surely, 2103010120027 is an apocalyptic number.

103010120027 is a deficient number, since it is larger than the sum of its proper divisors (1).

103010120027 is an equidigital number, since it uses as much as digits as its factorization.

103010120027 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 84, while the sum is 17.

Adding to 103010120027 its reverse (720021010301), we get a palindrome (823031130328).

The spelling of 103010120027 in words is "one hundred three billion, ten million, one hundred twenty thousand, twenty-seven".