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103010131331 is a prime number
BaseRepresentation
bin101111111101111100…
…0011101110110000011
3100211212221201212011022
41133323320131312003
53141431043200311
6115153332340055
710304454445412
oct1377370356603
9324787655138
10103010131331
113a760596348
1217b69a7462b
139938330543
144db2b43479
152a2d6305db
hex17fbe1dd83

103010131331 has 2 divisors, whose sum is σ = 103010131332. Its totient is φ = 103010131330.

The previous prime is 103010131319. The next prime is 103010131333. The reversal of 103010131331 is 133131010301.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 103010131331 - 214 = 103010114947 is a prime.

It is a super-2 number, since 2×1030101313312 (a number of 23 digits) contains 22 as substring.

Together with 103010131333, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (103010131333) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51505065665 + 51505065666.

It is an arithmetic number, because the mean of its divisors is an integer number (51505065666).

Almost surely, 2103010131331 is an apocalyptic number.

103010131331 is a deficient number, since it is larger than the sum of its proper divisors (1).

103010131331 is an equidigital number, since it uses as much as digits as its factorization.

103010131331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 103010131331 its reverse (133131010301), we get a palindrome (236141141632).

The spelling of 103010131331 in words is "one hundred three billion, ten million, one hundred thirty-one thousand, three hundred thirty-one".