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103011020222147 is a prime number
BaseRepresentation
bin10111011011000000011111…
…010001001010111011000011
3111111201202110010002002112122
4113123000133101022323003
5102000213032134102042
61003030335343514455
730461205052555022
oct2733003721127303
9444652403062478
10103011020222147
112a905801472964
12b6782862b8a2b
134562b88b30a4b
141b61a8d5608b9
15bd98467497d2
hex5db01f44aec3

103011020222147 has 2 divisors, whose sum is σ = 103011020222148. Its totient is φ = 103011020222146.

The previous prime is 103011020222093. The next prime is 103011020222171. The reversal of 103011020222147 is 741222020110301.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 103011020222147 - 238 = 102736142315203 is a prime.

It is a super-3 number, since 3×1030110202221473 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (103011023222147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51505510111073 + 51505510111074.

It is an arithmetic number, because the mean of its divisors is an integer number (51505510111074).

Almost surely, 2103011020222147 is an apocalyptic number.

103011020222147 is a deficient number, since it is larger than the sum of its proper divisors (1).

103011020222147 is an equidigital number, since it uses as much as digits as its factorization.

103011020222147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1344, while the sum is 26.

Adding to 103011020222147 its reverse (741222020110301), we get a palindrome (844233040332448).

The spelling of 103011020222147 in words is "one hundred three trillion, eleven billion, twenty million, two hundred twenty-two thousand, one hundred forty-seven".