103011113 has 2 divisors, whose sum is σ = 103011114. Its totient is φ = 103011112.

The previous prime is 103011079. The next prime is 103011121. The reversal of 103011113 is 311110301.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 101042704 + 1968409 = 10052^2 + 1403^2 .

It is a cyclic number.

It is not a de Polignac number, because 103011113 - 2⁶ = 103011049 is a prime.

It is a super-2 number, since 2×103011113² = 21222578802997538, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 103011094 and 103011103.

It is not a weakly prime, because it can be changed into another prime (103011163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51505556 + 51505557.

It is an arithmetic number, because the mean of its divisors is an integer number (51505557).

Almost surely, 2^103011113 is an apocalyptic number.

It is an amenable number.

103011113 is a deficient number, since it is larger than the sum of its proper divisors (1).

103011113 is an equidigital number, since it uses as much as digits as its factorization.

103011113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9, while the sum is 11.

The square root of 103011113 is about 10149.4390485386. The cubic root of 103011113 is about 468.7716726454.

Adding to 103011113 its reverse (311110301), we get a palindrome (414121414).

The spelling of 103011113 in words is "one hundred three million, eleven thousand, one hundred thirteen".