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103011317 is a prime number
BaseRepresentation
bin1100010001111…
…01001111110101
321011211111221222
412020331033311
5202332330232
614115520125
72360403353
oct610751765
9234744858
10103011317
1153168a22
122a5b9045
1318459356
14d9767d3
15909bd12
hex623d3f5

103011317 has 2 divisors, whose sum is σ = 103011318. Its totient is φ = 103011316.

The previous prime is 103011301. The next prime is 103011323. The reversal of 103011317 is 713110301.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 99480676 + 3530641 = 9974^2 + 1879^2 .

It is an emirp because it is prime and its reverse (713110301) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 103011317 - 24 = 103011301 is a prime.

It is a super-4 number, since 4×1030113174 (a number of 33 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 103011295 and 103011304.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (103011017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51505658 + 51505659.

It is an arithmetic number, because the mean of its divisors is an integer number (51505659).

Almost surely, 2103011317 is an apocalyptic number.

It is an amenable number.

103011317 is a deficient number, since it is larger than the sum of its proper divisors (1).

103011317 is an equidigital number, since it uses as much as digits as its factorization.

103011317 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 63, while the sum is 17.

The square root of 103011317 is about 10149.4490983501. The cubic root of 103011317 is about 468.7719820921.

Adding to 103011317 its reverse (713110301), we get a palindrome (816121618).

The spelling of 103011317 in words is "one hundred three million, eleven thousand, three hundred seventeen".