Base | Representation |
---|---|
bin | 10111011011000000110001… |
… | …001101000000111000010011 |
3 | 111111201210020002021101222121 |
4 | 113123000301031000320103 |
5 | 102000214141201403243 |
6 | 1003030425253115111 |
7 | 30461215365304015 |
oct | 2733006115007023 |
9 | 444653202241877 |
10 | 103011321122323 |
11 | 2a905946301699 |
12 | b67834b028a97 |
13 | 4562c062854a3 |
14 | 1b61abb4ca1b5 |
15 | bd9862d851ed |
hex | 5db031340e13 |
103011321122323 has 2 divisors, whose sum is σ = 103011321122324. Its totient is φ = 103011321122322.
The previous prime is 103011321122293. The next prime is 103011321122377. The reversal of 103011321122323 is 323221123110301.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 103011321122323 - 25 = 103011321122291 is a prime.
It is a super-3 number, since 3×1030113211223233 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (103011321122383) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51505660561161 + 51505660561162.
It is an arithmetic number, because the mean of its divisors is an integer number (51505660561162).
Almost surely, 2103011321122323 is an apocalyptic number.
103011321122323 is a deficient number, since it is larger than the sum of its proper divisors (1).
103011321122323 is an equidigital number, since it uses as much as digits as its factorization.
103011321122323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 103011321122323 its reverse (323221123110301), we get a palindrome (426232444232624).
The spelling of 103011321122323 in words is "one hundred three trillion, eleven billion, three hundred twenty-one million, one hundred twenty-two thousand, three hundred twenty-three".
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