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103011321122323 is a prime number
BaseRepresentation
bin10111011011000000110001…
…001101000000111000010011
3111111201210020002021101222121
4113123000301031000320103
5102000214141201403243
61003030425253115111
730461215365304015
oct2733006115007023
9444653202241877
10103011321122323
112a905946301699
12b67834b028a97
134562c062854a3
141b61abb4ca1b5
15bd9862d851ed
hex5db031340e13

103011321122323 has 2 divisors, whose sum is σ = 103011321122324. Its totient is φ = 103011321122322.

The previous prime is 103011321122293. The next prime is 103011321122377. The reversal of 103011321122323 is 323221123110301.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 103011321122323 - 25 = 103011321122291 is a prime.

It is a super-3 number, since 3×1030113211223233 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (103011321122383) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51505660561161 + 51505660561162.

It is an arithmetic number, because the mean of its divisors is an integer number (51505660561162).

Almost surely, 2103011321122323 is an apocalyptic number.

103011321122323 is a deficient number, since it is larger than the sum of its proper divisors (1).

103011321122323 is an equidigital number, since it uses as much as digits as its factorization.

103011321122323 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 103011321122323 its reverse (323221123110301), we get a palindrome (426232444232624).

The spelling of 103011321122323 in words is "one hundred three trillion, eleven billion, three hundred twenty-one million, one hundred twenty-two thousand, three hundred twenty-three".