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1030135681951 is a prime number
BaseRepresentation
bin11101111110110001101…
…11110001001110011111
310122110221221000200111121
432333120313301032133
5113334204213310301
62105123210431411
7134265502552045
oct16773067611637
93573857020447
101030135681951
11367972811872
12147792432567
13761ab7b86cc
1437c048d0395
151bbe22423a1
hexefd8df139f

1030135681951 has 2 divisors, whose sum is σ = 1030135681952. Its totient is φ = 1030135681950.

The previous prime is 1030135681933. The next prime is 1030135681963. The reversal of 1030135681951 is 1591865310301.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1030135681951 - 25 = 1030135681919 is a prime.

It is a super-2 number, since 2×10301356819512 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1030135681898 and 1030135681907.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1030135681921) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515067840975 + 515067840976.

It is an arithmetic number, because the mean of its divisors is an integer number (515067840976).

Almost surely, 21030135681951 is an apocalyptic number.

1030135681951 is a deficient number, since it is larger than the sum of its proper divisors (1).

1030135681951 is an equidigital number, since it uses as much as digits as its factorization.

1030135681951 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 97200, while the sum is 43.

The spelling of 1030135681951 in words is "one trillion, thirty billion, one hundred thirty-five million, six hundred eighty-one thousand, nine hundred fifty-one".