Base | Representation |
---|---|
bin | 11101111110110011110… |
… | …10011010111000010111 |
3 | 10122111000010220100202011 |
4 | 32333121322122320113 |
5 | 113334223201412241 |
6 | 2105125033125051 |
7 | 134266104222136 |
oct | 16773172327027 |
9 | 3574003810664 |
10 | 1030153154071 |
11 | 367981665938 |
12 | 147798259787 |
13 | 761b22c5342 |
14 | 37c06d5b91d |
15 | 1bbe3a44281 |
hex | efd9e9ae17 |
1030153154071 has 2 divisors, whose sum is σ = 1030153154072. Its totient is φ = 1030153154070.
The previous prime is 1030153154059. The next prime is 1030153154089. The reversal of 1030153154071 is 1704513510301.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1030153154071 - 227 = 1030018936343 is a prime.
It is a super-2 number, since 2×10301531540712 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1030153154671) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515076577035 + 515076577036.
It is an arithmetic number, because the mean of its divisors is an integer number (515076577036).
Almost surely, 21030153154071 is an apocalyptic number.
1030153154071 is a deficient number, since it is larger than the sum of its proper divisors (1).
1030153154071 is an equidigital number, since it uses as much as digits as its factorization.
1030153154071 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6300, while the sum is 31.
Adding to 1030153154071 its reverse (1704513510301), we get a palindrome (2734666664372).
The spelling of 1030153154071 in words is "one trillion, thirty billion, one hundred fifty-three million, one hundred fifty-four thousand, seventy-one".
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