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103020362017 is a prime number
BaseRepresentation
bin101111111110001111…
…1011111100100100001
3100211220122222122000121
41133330133133210201
53141441203041032
6115154335520241
710304640425446
oct1377437374441
9324818878017
10103020362017
113a766343861
1217b71389081
13993a4a30c1
144db42479cd
152a2e4a1a97
hex17fc7df921

103020362017 has 2 divisors, whose sum is σ = 103020362018. Its totient is φ = 103020362016.

The previous prime is 103020361963. The next prime is 103020362047. The reversal of 103020362017 is 710263020301.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 78084478096 + 24935883921 = 279436^2 + 157911^2 .

It is an emirp because it is prime and its reverse (710263020301) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 103020362017 - 231 = 100872878369 is a prime.

It is a super-2 number, since 2×1030203620172 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 103020361982 and 103020362000.

It is not a weakly prime, because it can be changed into another prime (103020362047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51510181008 + 51510181009.

It is an arithmetic number, because the mean of its divisors is an integer number (51510181009).

Almost surely, 2103020362017 is an apocalyptic number.

It is an amenable number.

103020362017 is a deficient number, since it is larger than the sum of its proper divisors (1).

103020362017 is an equidigital number, since it uses as much as digits as its factorization.

103020362017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1512, while the sum is 25.

Adding to 103020362017 its reverse (710263020301), we get a palindrome (813283382318).

The spelling of 103020362017 in words is "one hundred three billion, twenty million, three hundred sixty-two thousand, seventeen".