Base | Representation |
---|---|
bin | 101111111110001111… |
… | …1110010111011100101 |
3 | 100211220200010122210122 |
4 | 1133330133302323211 |
5 | 3141441213110232 |
6 | 115154341331325 |
7 | 10304641205603 |
oct | 1377437627345 |
9 | 324820118718 |
10 | 103020441317 |
11 | 3a7663983a2 |
12 | 17b71406b45 |
13 | 993a500221 |
14 | 4db4268873 |
15 | 2a2e4ba312 |
hex | 17fc7f2ee5 |
103020441317 has 2 divisors, whose sum is σ = 103020441318. Its totient is φ = 103020441316.
The previous prime is 103020441311. The next prime is 103020441347. The reversal of 103020441317 is 713144020301.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 75426580321 + 27593860996 = 274639^2 + 166114^2 .
It is a cyclic number.
It is not a de Polignac number, because 103020441317 - 28 = 103020441061 is a prime.
It is a super-2 number, since 2×1030204413172 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (103020441311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51510220658 + 51510220659.
It is an arithmetic number, because the mean of its divisors is an integer number (51510220659).
Almost surely, 2103020441317 is an apocalyptic number.
It is an amenable number.
103020441317 is a deficient number, since it is larger than the sum of its proper divisors (1).
103020441317 is an equidigital number, since it uses as much as digits as its factorization.
103020441317 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2016, while the sum is 26.
Adding to 103020441317 its reverse (713144020301), we get a palindrome (816164461618).
The spelling of 103020441317 in words is "one hundred three billion, twenty million, four hundred forty-one thousand, three hundred seventeen".
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