Base | Representation |
---|---|
bin | 11101111110111010001… |
… | …10000000100110011111 |
3 | 10122111010212022211021001 |
4 | 32333131012000212133 |
5 | 113334330332230212 |
6 | 2105134221051131 |
7 | 134300322653056 |
oct | 16773506004637 |
9 | 3574125284231 |
10 | 1030206523807 |
11 | 3679a97a835a |
12 | 1477b20b6aa7 |
13 | 761c0390476 |
14 | 37c1009139d |
15 | 1bbe8587657 |
hex | efdd18099f |
1030206523807 has 2 divisors, whose sum is σ = 1030206523808. Its totient is φ = 1030206523806.
The previous prime is 1030206523799. The next prime is 1030206523813. The reversal of 1030206523807 is 7083256020301.
It is a strong prime.
It is an emirp because it is prime and its reverse (7083256020301) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1030206523807 - 23 = 1030206523799 is a prime.
It is a super-2 number, since 2×10302065238072 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1030206523837) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515103261903 + 515103261904.
It is an arithmetic number, because the mean of its divisors is an integer number (515103261904).
Almost surely, 21030206523807 is an apocalyptic number.
1030206523807 is a deficient number, since it is larger than the sum of its proper divisors (1).
1030206523807 is an equidigital number, since it uses as much as digits as its factorization.
1030206523807 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 60480, while the sum is 37.
The spelling of 1030206523807 in words is "one trillion, thirty billion, two hundred six million, five hundred twenty-three thousand, eight hundred seven".
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