Base | Representation |
---|---|
bin | 10111011011001010101101… |
… | …111001111010000010100011 |
3 | 111111202210210112111012000012 |
4 | 113123022231321322002203 |
5 | 102000403030304401123 |
6 | 1003035353243115135 |
7 | 30462044164414055 |
oct | 2733125571720243 |
9 | 444683715435005 |
10 | 103022003200163 |
11 | 2a90a4280348a3 |
12 | b67a430512aab |
13 | 4563c193785c8 |
14 | 1b6241207d8d5 |
15 | bd9c8aa75378 |
hex | 5db2ade7a0a3 |
103022003200163 has 2 divisors, whose sum is σ = 103022003200164. Its totient is φ = 103022003200162.
The previous prime is 103022003200157. The next prime is 103022003200169. The reversal of 103022003200163 is 361002300220301.
It is a balanced prime because it is at equal distance from previous prime (103022003200157) and next prime (103022003200169).
It is a cyclic number.
It is not a de Polignac number, because 103022003200163 - 210 = 103022003199139 is a prime.
It is a super-2 number, since 2×1030220032001632 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (103022003200169) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51511001600081 + 51511001600082.
It is an arithmetic number, because the mean of its divisors is an integer number (51511001600082).
Almost surely, 2103022003200163 is an apocalyptic number.
103022003200163 is a deficient number, since it is larger than the sum of its proper divisors (1).
103022003200163 is an equidigital number, since it uses as much as digits as its factorization.
103022003200163 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 103022003200163 its reverse (361002300220301), we get a palindrome (464024303420464).
The spelling of 103022003200163 in words is "one hundred three trillion, twenty-two billion, three million, two hundred thousand, one hundred sixty-three".
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