Base | Representation |
---|---|
bin | 11101111110111100010… |
… | …01110100110001001111 |
3 | 10122111012002210000011121 |
4 | 32333132021310301033 |
5 | 113334344410114020 |
6 | 2105140054101411 |
7 | 134300630034031 |
oct | 16773611646117 |
9 | 3574162700147 |
10 | 1030224301135 |
11 | 367a0883a767 |
12 | 1477b804a867 |
13 | 761c3c75cb3 |
14 | 37c1259bc51 |
15 | 1bbe9de9baa |
hex | efde274c4f |
1030224301135 has 8 divisors (see below), whose sum is σ = 1236287102400. Its totient is φ = 824167480224.
The previous prime is 1030224301121. The next prime is 1030224301193. The reversal of 1030224301135 is 5311034220301.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1030224301135 - 213 = 1030224292943 is a prime.
It is a super-2 number, since 2×10302243011352 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1106935 + ... + 1812664.
It is an arithmetic number, because the mean of its divisors is an integer number (154535887800).
Almost surely, 21030224301135 is an apocalyptic number.
1030224301135 is a deficient number, since it is larger than the sum of its proper divisors (206062801265).
1030224301135 is an equidigital number, since it uses as much as digits as its factorization.
1030224301135 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2990177.
The product of its (nonzero) digits is 2160, while the sum is 25.
Adding to 1030224301135 its reverse (5311034220301), we get a palindrome (6341258521436).
The spelling of 1030224301135 in words is "one trillion, thirty billion, two hundred twenty-four million, three hundred one thousand, one hundred thirty-five".
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