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1030243314131 is a prime number
BaseRepresentation
bin11101111110111110100…
…10010110100111010011
310122111020102112222002122
432333133102112213103
5113334414242023011
62105142013404455
7134301250452353
oct16773722264723
93574212488078
101030243314131
11367a18546489
1214780249972b
13761c7ba20a5
1437c14d0ab63
151bbeb9033db
hexefdf4969d3

1030243314131 has 2 divisors, whose sum is σ = 1030243314132. Its totient is φ = 1030243314130.

The previous prime is 1030243314097. The next prime is 1030243314157. The reversal of 1030243314131 is 1314133420301.

It is an a-pointer prime, because the next prime (1030243314157) can be obtained adding 1030243314131 to its sum of digits (26).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1030243314131 - 218 = 1030243051987 is a prime.

It is a super-2 number, since 2×10302433141312 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1030243314131.

It is not a weakly prime, because it can be changed into another prime (1030243314031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515121657065 + 515121657066.

It is an arithmetic number, because the mean of its divisors is an integer number (515121657066).

Almost surely, 21030243314131 is an apocalyptic number.

1030243314131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1030243314131 is an equidigital number, since it uses as much as digits as its factorization.

1030243314131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2592, while the sum is 26.

Adding to 1030243314131 its reverse (1314133420301), we get a palindrome (2344376734432).

The spelling of 1030243314131 in words is "one trillion, thirty billion, two hundred forty-three million, three hundred fourteen thousand, one hundred thirty-one".