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1030311201317 is a prime number
BaseRepresentation
bin11101111111000110101…
…01010100101000100101
310122111102011021222210212
432333203111110220211
5113340034131420232
62105152440425205
7134303033466236
oct16774325245045
93574364258725
101030311201317
11367a528a40a2
12147821178205
1376208c81018
1437c1dd3d08d
151bc02862eb2
hexefe3554a25

1030311201317 has 2 divisors, whose sum is σ = 1030311201318. Its totient is φ = 1030311201316.

The previous prime is 1030311201281. The next prime is 1030311201397. The reversal of 1030311201317 is 7131021130301.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1024729019521 + 5582181796 = 1012289^2 + 74714^2 .

It is an emirp because it is prime and its reverse (7131021130301) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1030311201317 - 224 = 1030294424101 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1030311201292 and 1030311201301.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1030311201397) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515155600658 + 515155600659.

It is an arithmetic number, because the mean of its divisors is an integer number (515155600659).

Almost surely, 21030311201317 is an apocalyptic number.

It is an amenable number.

1030311201317 is a deficient number, since it is larger than the sum of its proper divisors (1).

1030311201317 is an equidigital number, since it uses as much as digits as its factorization.

1030311201317 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 378, while the sum is 23.

Adding to 1030311201317 its reverse (7131021130301), we get a palindrome (8161332331618).

The spelling of 1030311201317 in words is "one trillion, thirty billion, three hundred eleven million, two hundred one thousand, three hundred seventeen".