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1030501312231 is a prime number
BaseRepresentation
bin11101111111011101010…
…10100010011011100111
310122111220102000121221211
432333232222202123213
5113340431313442411
62105223351252251
7134310532425406
oct16775652423347
93574812017854
101030501312231
11368040142256
1214787497a087
13762394850a1
1437c3b2a963d
151bc143b7221
hexefeeaa26e7

1030501312231 has 2 divisors, whose sum is σ = 1030501312232. Its totient is φ = 1030501312230.

The previous prime is 1030501312223. The next prime is 1030501312237. The reversal of 1030501312231 is 1322131050301.

It is a strong prime.

It is an emirp because it is prime and its reverse (1322131050301) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1030501312231 - 23 = 1030501312223 is a prime.

It is a super-2 number, since 2×10305013122312 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1030501312237) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515250656115 + 515250656116.

It is an arithmetic number, because the mean of its divisors is an integer number (515250656116).

Almost surely, 21030501312231 is an apocalyptic number.

1030501312231 is a deficient number, since it is larger than the sum of its proper divisors (1).

1030501312231 is an equidigital number, since it uses as much as digits as its factorization.

1030501312231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 540, while the sum is 22.

Adding to 1030501312231 its reverse (1322131050301), we get a palindrome (2352632362532).

The spelling of 1030501312231 in words is "one trillion, thirty billion, five hundred one million, three hundred twelve thousand, two hundred thirty-one".