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10305341437 is a prime number
BaseRepresentation
bin10011001100011111…
…10000011111111101
3222121012022120211111
421212033300133331
5132101131411222
64422331122021
7513242646136
oct114617603775
928535276744
1010305341437
114409107606
121bb72a3311
13c83038591
146da926c8d
15404ac4777
hex2663f07fd

10305341437 has 2 divisors, whose sum is σ = 10305341438. Its totient is φ = 10305341436.

The previous prime is 10305341419. The next prime is 10305341447. The reversal of 10305341437 is 73414350301.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5946568996 + 4358772441 = 77114^2 + 66021^2 .

It is a cyclic number.

It is not a de Polignac number, because 10305341437 - 227 = 10171123709 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10305341399 and 10305341408.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10305341447) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5152670718 + 5152670719.

It is an arithmetic number, because the mean of its divisors is an integer number (5152670719).

Almost surely, 210305341437 is an apocalyptic number.

It is an amenable number.

10305341437 is a deficient number, since it is larger than the sum of its proper divisors (1).

10305341437 is an equidigital number, since it uses as much as digits as its factorization.

10305341437 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15120, while the sum is 31.

Adding to 10305341437 its reverse (73414350301), we get a palindrome (83719691738).

The spelling of 10305341437 in words is "ten billion, three hundred five million, three hundred forty-one thousand, four hundred thirty-seven".