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10309433 is a prime number
BaseRepresentation
bin100111010100…
…111100111001
3201101202212212
4213110330321
510114400213
61004544505
7153425441
oct47247471
921352785
1010309433
1159016a2
123552135
13219c674
141525121
15d899a8
hex9d4f39

10309433 has 2 divisors, whose sum is σ = 10309434. Its totient is φ = 10309432.

The previous prime is 10309423. The next prime is 10309447. The reversal of 10309433 is 33490301.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9412624 + 896809 = 3068^2 + 947^2 .

It is a cyclic number.

It is not a de Polignac number, because 10309433 - 24 = 10309417 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 10309399 and 10309408.

It is not a weakly prime, because it can be changed into another prime (10309423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5154716 + 5154717.

It is an arithmetic number, because the mean of its divisors is an integer number (5154717).

Almost surely, 210309433 is an apocalyptic number.

It is an amenable number.

10309433 is a deficient number, since it is larger than the sum of its proper divisors (1).

10309433 is an equidigital number, since it uses as much as digits as its factorization.

10309433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 972, while the sum is 23.

The square root of 10309433 is about 3210.8305779035. The cubic root of 10309433 is about 217.6431118736.

Adding to 10309433 its reverse (33490301), we get a palindrome (43799734).

The spelling of 10309433 in words is "ten million, three hundred nine thousand, four hundred thirty-three".