Base | Representation |
---|---|
bin | 11110000000011000111… |
… | …00111001000001110101 |
3 | 10122120012020101000000111 |
4 | 33000030130321001311 |
5 | 113342442232120003 |
6 | 2105345122343021 |
7 | 134326111224445 |
oct | 17001434710165 |
9 | 3576166330014 |
10 | 1031001051253 |
11 | 368277240608 |
12 | 1479941baa71 |
13 | 762b8b78454 |
14 | 37c877d4125 |
15 | 1bc431cce6d |
hex | f00c739075 |
1031001051253 has 2 divisors, whose sum is σ = 1031001051254. Its totient is φ = 1031001051252.
The previous prime is 1031001051217. The next prime is 1031001051259. The reversal of 1031001051253 is 3521501001301.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 651671936644 + 379329114609 = 807262^2 + 615897^2 .
It is a cyclic number.
It is not a de Polignac number, because 1031001051253 - 221 = 1030998954101 is a prime.
It is a super-2 number, since 2×10310010512532 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1031001051259) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515500525626 + 515500525627.
It is an arithmetic number, because the mean of its divisors is an integer number (515500525627).
Almost surely, 21031001051253 is an apocalyptic number.
It is an amenable number.
1031001051253 is a deficient number, since it is larger than the sum of its proper divisors (1).
1031001051253 is an equidigital number, since it uses as much as digits as its factorization.
1031001051253 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 450, while the sum is 22.
Adding to 1031001051253 its reverse (3521501001301), we get a palindrome (4552502052554).
The spelling of 1031001051253 in words is "one trillion, thirty-one billion, one million, fifty-one thousand, two hundred fifty-three".
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