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1031001051253 is a prime number
BaseRepresentation
bin11110000000011000111…
…00111001000001110101
310122120012020101000000111
433000030130321001311
5113342442232120003
62105345122343021
7134326111224445
oct17001434710165
93576166330014
101031001051253
11368277240608
121479941baa71
13762b8b78454
1437c877d4125
151bc431cce6d
hexf00c739075

1031001051253 has 2 divisors, whose sum is σ = 1031001051254. Its totient is φ = 1031001051252.

The previous prime is 1031001051217. The next prime is 1031001051259. The reversal of 1031001051253 is 3521501001301.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 651671936644 + 379329114609 = 807262^2 + 615897^2 .

It is a cyclic number.

It is not a de Polignac number, because 1031001051253 - 221 = 1030998954101 is a prime.

It is a super-2 number, since 2×10310010512532 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1031001051259) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515500525626 + 515500525627.

It is an arithmetic number, because the mean of its divisors is an integer number (515500525627).

Almost surely, 21031001051253 is an apocalyptic number.

It is an amenable number.

1031001051253 is a deficient number, since it is larger than the sum of its proper divisors (1).

1031001051253 is an equidigital number, since it uses as much as digits as its factorization.

1031001051253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 450, while the sum is 22.

Adding to 1031001051253 its reverse (3521501001301), we get a palindrome (4552502052554).

The spelling of 1031001051253 in words is "one trillion, thirty-one billion, one million, fifty-one thousand, two hundred fifty-three".