Base | Representation |
---|---|
bin | 1001011000000111110010… |
… | …0111011001001110000111 |
3 | 1100111121221110220100112222 |
4 | 2112001330213121032013 |
5 | 2322404401111241403 |
6 | 33532204302402555 |
7 | 2112605466563462 |
oct | 226017447311607 |
9 | 40447843810488 |
10 | 10310012212103 |
11 | 33154a712647a |
12 | 11a619629045b |
13 | 59a2cb35bc96 |
14 | 279015c922d9 |
15 | 12d2c15c3338 |
hex | 9607c9d9387 |
10310012212103 has 2 divisors, whose sum is σ = 10310012212104. Its totient is φ = 10310012212102.
The previous prime is 10310012212061. The next prime is 10310012212127. The reversal of 10310012212103 is 30121221001301.
10310012212103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10310012212103 - 220 = 10310011163527 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10310012212163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5155006106051 + 5155006106052.
It is an arithmetic number, because the mean of its divisors is an integer number (5155006106052).
Almost surely, 210310012212103 is an apocalyptic number.
10310012212103 is a deficient number, since it is larger than the sum of its proper divisors (1).
10310012212103 is an equidigital number, since it uses as much as digits as its factorization.
10310012212103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 10310012212103 its reverse (30121221001301), we get a palindrome (40431233213404).
The spelling of 10310012212103 in words is "ten trillion, three hundred ten billion, twelve million, two hundred twelve thousand, one hundred three".
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