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103100222131069 is a prime number
BaseRepresentation
bin10111011100010011100100…
…000111011100101101111101
3111112001021200202012120112011
4113130103210013130231331
5102003143223331143234
61003135331014211221
730500513421355312
oct2734234407345575
9445037622176464
10103100222131069
112a93a616637349
12b69161b953b11
13456b4034bac87
141b6611246cd09
15bdbd179c9b64
hex5dc4e41dcb7d

103100222131069 has 2 divisors, whose sum is σ = 103100222131070. Its totient is φ = 103100222131068.

The previous prime is 103100222131003. The next prime is 103100222131129. The reversal of 103100222131069 is 960131222001301.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 103007783025625 + 92439105444 = 10149275^2 + 304038^2 .

It is a cyclic number.

It is not a de Polignac number, because 103100222131069 - 227 = 103100087913341 is a prime.

It is a super-2 number, since 2×1031002221310692 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 103100222131069.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (103100222134069) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51550111065534 + 51550111065535.

It is an arithmetic number, because the mean of its divisors is an integer number (51550111065535).

Almost surely, 2103100222131069 is an apocalyptic number.

It is an amenable number.

103100222131069 is a deficient number, since it is larger than the sum of its proper divisors (1).

103100222131069 is an equidigital number, since it uses as much as digits as its factorization.

103100222131069 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3888, while the sum is 31.

The spelling of 103100222131069 in words is "one hundred three trillion, one hundred billion, two hundred twenty-two million, one hundred thirty-one thousand, sixty-nine".