Base | Representation |
---|---|
bin | 11110000000011001001… |
… | …01110110110001111101 |
3 | 10122120012101210101201210 |
4 | 33000030211312301331 |
5 | 113342443332320331 |
6 | 2105345244555033 |
7 | 134326140213144 |
oct | 17001445666175 |
9 | 3576171711653 |
10 | 1031003401341 |
11 | 3682785a6231 |
12 | 147994b52a79 |
13 | 762b94bc034 |
14 | 37c87c4675b |
15 | 1bc434e4446 |
hex | f00c976c7d |
1031003401341 has 64 divisors (see below), whose sum is σ = 1464322083840. Its totient is φ = 644339888640.
The previous prime is 1031003401333. The next prime is 1031003401361. The reversal of 1031003401341 is 1431043001301.
It is not a de Polignac number, because 1031003401341 - 23 = 1031003401333 is a prime.
It is a super-2 number, since 2×10310034013412 (a number of 25 digits) contains 22 as substring.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1031003401301) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 321283345 + ... + 321286553.
It is an arithmetic number, because the mean of its divisors is an integer number (22880032560).
Almost surely, 21031003401341 is an apocalyptic number.
It is an amenable number.
1031003401341 is a deficient number, since it is larger than the sum of its proper divisors (433318682499).
1031003401341 is a wasteful number, since it uses less digits than its factorization.
1031003401341 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4186.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 1031003401341 its reverse (1431043001301), we get a palindrome (2462046402642).
The spelling of 1031003401341 in words is "one trillion, thirty-one billion, three million, four hundred one thousand, three hundred forty-one".
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