Base | Representation |
---|---|
bin | 10111011100010100011001… |
… | …101001010100001000000111 |
3 | 111112001101000100002021011201 |
4 | 113130110121221110020013 |
5 | 102003202043232414343 |
6 | 1003140000055043331 |
7 | 30500544605005534 |
oct | 2734243151241007 |
9 | 445041010067151 |
10 | 103101120201223 |
11 | 2a93aa37570791 |
12 | b691830670547 |
13 | 456b51758a131 |
14 | 1b66199845d8b |
15 | bdbd6b77494d |
hex | 5dc519a54207 |
103101120201223 has 2 divisors, whose sum is σ = 103101120201224. Its totient is φ = 103101120201222.
The previous prime is 103101120201203. The next prime is 103101120201307. The reversal of 103101120201223 is 322102021101301.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 103101120201223 - 237 = 102963681247751 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 103101120201223.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (103101120201203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51550560100611 + 51550560100612.
It is an arithmetic number, because the mean of its divisors is an integer number (51550560100612).
Almost surely, 2103101120201223 is an apocalyptic number.
103101120201223 is a deficient number, since it is larger than the sum of its proper divisors (1).
103101120201223 is an equidigital number, since it uses as much as digits as its factorization.
103101120201223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 103101120201223 its reverse (322102021101301), we get a palindrome (425203141302524).
The spelling of 103101120201223 in words is "one hundred three trillion, one hundred one billion, one hundred twenty million, two hundred one thousand, two hundred twenty-three".
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