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103101121153 is a prime number
BaseRepresentation
bin110000000000101001…
…1100100001010000001
3100212010021221121201201
41200001103210022001
53142122341334103
6115210342501201
710306641033022
oct1400123441201
9325107847651
10103101121153
113a7a7993348
1217b94434801
13995113ab84
144dc0c6ac49
152a3660551d
hex18014e4281

103101121153 has 2 divisors, whose sum is σ = 103101121154. Its totient is φ = 103101121152.

The previous prime is 103101121133. The next prime is 103101121159. The reversal of 103101121153 is 351121101301.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 62546008464 + 40555112689 = 250092^2 + 201383^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-103101121153 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 103101121153.

It is not a weakly prime, because it can be changed into another prime (103101121159) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51550560576 + 51550560577.

It is an arithmetic number, because the mean of its divisors is an integer number (51550560577).

Almost surely, 2103101121153 is an apocalyptic number.

It is an amenable number.

103101121153 is a deficient number, since it is larger than the sum of its proper divisors (1).

103101121153 is an equidigital number, since it uses as much as digits as its factorization.

103101121153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 90, while the sum is 19.

Adding to 103101121153 its reverse (351121101301), we get a palindrome (454222222454).

The spelling of 103101121153 in words is "one hundred three billion, one hundred one million, one hundred twenty-one thousand, one hundred fifty-three".