Base | Representation |
---|---|
bin | 10011001101000100… |
… | …00010010110001011 |
3 | 222121112100000210122 |
4 | 21212202002112023 |
5 | 132103343230011 |
6 | 4423021533455 |
7 | 513331454114 |
oct | 114642022613 |
9 | 28545300718 |
10 | 10310133131 |
11 | 441088a691 |
12 | 1bb8a1428b |
13 | c840255bc |
14 | 6db41320b |
15 | 40521e3db |
hex | 26688258b |
10310133131 has 2 divisors, whose sum is σ = 10310133132. Its totient is φ = 10310133130.
The previous prime is 10310133073. The next prime is 10310133133. The reversal of 10310133131 is 13133101301.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-10310133131 is a prime.
It is a super-2 number, since 2×103101331312 (a number of 21 digits) contains 22 as substring.
Together with 10310133133, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (10310133133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5155066565 + 5155066566.
It is an arithmetic number, because the mean of its divisors is an integer number (5155066566).
Almost surely, 210310133131 is an apocalyptic number.
10310133131 is a deficient number, since it is larger than the sum of its proper divisors (1).
10310133131 is an equidigital number, since it uses as much as digits as its factorization.
10310133131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 81, while the sum is 17.
Adding to 10310133131 its reverse (13133101301), we get a palindrome (23443234432).
The spelling of 10310133131 in words is "ten billion, three hundred ten million, one hundred thirty-three thousand, one hundred thirty-one".
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