Base | Representation |
---|---|
bin | 110000000000101011… |
… | …1101011110100111111 |
3 | 100212010100222111012122 |
4 | 1200001113223310333 |
5 | 3142123130414101 |
6 | 115210421553155 |
7 | 10306653151505 |
oct | 1400127536477 |
9 | 325110874178 |
10 | 103102201151 |
11 | 3a7a8560804 |
12 | 17b948757bb |
13 | 9951428621 |
14 | 4dc106c675 |
15 | 2a3676a51b |
hex | 18015ebd3f |
103102201151 has 2 divisors, whose sum is σ = 103102201152. Its totient is φ = 103102201150.
The previous prime is 103102201109. The next prime is 103102201183. The reversal of 103102201151 is 151102201301.
It is a strong prime.
It is an emirp because it is prime and its reverse (151102201301) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 103102201151 - 214 = 103102184767 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (103102201051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51551100575 + 51551100576.
It is an arithmetic number, because the mean of its divisors is an integer number (51551100576).
Almost surely, 2103102201151 is an apocalyptic number.
103102201151 is a deficient number, since it is larger than the sum of its proper divisors (1).
103102201151 is an equidigital number, since it uses as much as digits as its factorization.
103102201151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 60, while the sum is 17.
Adding to 103102201151 its reverse (151102201301), we get a palindrome (254204402452).
The spelling of 103102201151 in words is "one hundred three billion, one hundred two million, two hundred one thousand, one hundred fifty-one".
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