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1031034404207 is a prime number
BaseRepresentation
bin11110000000011100111…
…00000111110101101111
310122120021120010111200002
433000032130013311233
5113343024301413312
62105352313254515
7134326664556413
oct17001634076557
93576246114602
101031034404207
11368294051135
121479a340443b
13762c2a55622
1437c8bdd6d43
151bc460ba4c2
hexf00e707d6f

1031034404207 has 2 divisors, whose sum is σ = 1031034404208. Its totient is φ = 1031034404206.

The previous prime is 1031034404201. The next prime is 1031034404219. The reversal of 1031034404207 is 7024044301301.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1031034404207 - 212 = 1031034400111 is a prime.

It is a super-4 number, since 4×10310344042074 (a number of 49 digits) contains 4444 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1031034404207.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1031034404201) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515517202103 + 515517202104.

It is an arithmetic number, because the mean of its divisors is an integer number (515517202104).

Almost surely, 21031034404207 is an apocalyptic number.

1031034404207 is a deficient number, since it is larger than the sum of its proper divisors (1).

1031034404207 is an equidigital number, since it uses as much as digits as its factorization.

1031034404207 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8064, while the sum is 29.

Adding to 1031034404207 its reverse (7024044301301), we get a palindrome (8055078705508).

The spelling of 1031034404207 in words is "one trillion, thirty-one billion, thirty-four million, four hundred four thousand, two hundred seven".