103110995129 has 2 divisors, whose sum is σ = 103110995130. Its totient is φ = 103110995128.

The previous prime is 103110995093. The next prime is 103110995131. The reversal of 103110995129 is 921599011301.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 83505394729 + 19605600400 = 288973^2 + 140020^2 .

It is an emirp because it is prime and its reverse (921599011301) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 103110995129 - 2¹² = 103110991033 is a prime.

Together with 103110995131, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (103110992129) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51555497564 + 51555497565.

It is an arithmetic number, because the mean of its divisors is an integer number (51555497565).

Almost surely, 2^103110995129 is an apocalyptic number.

It is an amenable number.

103110995129 is a deficient number, since it is larger than the sum of its proper divisors (1).

103110995129 is an equidigital number, since it uses as much as digits as its factorization.

103110995129 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 21870, while the sum is 41.

The spelling of 103110995129 in words is "one hundred three billion, one hundred ten million, nine hundred ninety-five thousand, one hundred twenty-nine".