Base | Representation |
---|---|
bin | 110000000000111100… |
… | …1010101001011110111 |
3 | 100212010222120121011221 |
4 | 1200001321111023313 |
5 | 3142132410140203 |
6 | 115211335011211 |
7 | 10310121135313 |
oct | 1400171251367 |
9 | 325128517157 |
10 | 103111021303 |
11 | 3a802535494 |
12 | 17b97809b07 |
13 | 99531c6154 |
14 | 4dc22c6b43 |
15 | 2a3740dabd |
hex | 1801e552f7 |
103111021303 has 2 divisors, whose sum is σ = 103111021304. Its totient is φ = 103111021302.
The previous prime is 103111021267. The next prime is 103111021361. The reversal of 103111021303 is 303120111301.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-103111021303 is a prime.
It is a super-3 number, since 3×1031110213033 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (103111021373) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51555510651 + 51555510652.
It is an arithmetic number, because the mean of its divisors is an integer number (51555510652).
Almost surely, 2103111021303 is an apocalyptic number.
103111021303 is a deficient number, since it is larger than the sum of its proper divisors (1).
103111021303 is an equidigital number, since it uses as much as digits as its factorization.
103111021303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 103111021303 its reverse (303120111301), we get a palindrome (406231132604).
The spelling of 103111021303 in words is "one hundred three billion, one hundred eleven million, twenty-one thousand, three hundred three".
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