Base | Representation |
---|---|
bin | 10111011100011101110010… |
… | …011100101100101110000101 |
3 | 111112002100000211000010212201 |
4 | 113130131302130230232011 |
5 | 102003333214200012101 |
6 | 1003144344212114501 |
7 | 30501352441620601 |
oct | 2734356234545605 |
9 | 445070024003781 |
10 | 103111200000901 |
11 | 2a94423a32a444 |
12 | b693784305a31 |
13 | 456c462967741 |
14 | 1b6687441c501 |
15 | bdc25b646e01 |
hex | 5dc77272cb85 |
103111200000901 has 2 divisors, whose sum is σ = 103111200000902. Its totient is φ = 103111200000900.
The previous prime is 103111200000859. The next prime is 103111200000917. The reversal of 103111200000901 is 109000002111301.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 97143219727876 + 5967980273025 = 9856126^2 + 2442945^2 .
It is a cyclic number.
It is not a de Polignac number, because 103111200000901 - 27 = 103111200000773 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (103111200000931) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51555600000450 + 51555600000451.
It is an arithmetic number, because the mean of its divisors is an integer number (51555600000451).
Almost surely, 2103111200000901 is an apocalyptic number.
It is an amenable number.
103111200000901 is a deficient number, since it is larger than the sum of its proper divisors (1).
103111200000901 is an equidigital number, since it uses as much as digits as its factorization.
103111200000901 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 19.
The spelling of 103111200000901 in words is "one hundred three trillion, one hundred eleven billion, two hundred million, nine hundred one", and thus it is an aban number.
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