Base | Representation |
---|---|
bin | 1001011000001011111011… |
… | …0001101010010111000111 |
3 | 1100111201210211112120201002 |
4 | 2112002332301222113013 |
5 | 2322414134240400012 |
6 | 33532510353323515 |
7 | 2112645135406016 |
oct | 226027661522707 |
9 | 40451724476632 |
10 | 10311122200007 |
11 | 3315a16742852 |
12 | 11a6445b6659b |
13 | 59a4472c8b65 |
14 | 2790bd470a7d |
15 | 12d338c7d7c2 |
hex | 960bec6a5c7 |
10311122200007 has 2 divisors, whose sum is σ = 10311122200008. Its totient is φ = 10311122200006.
The previous prime is 10311122199967. The next prime is 10311122200063. The reversal of 10311122200007 is 70000222111301.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10311122200007 - 218 = 10311121937863 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10311121200007) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5155561100003 + 5155561100004.
It is an arithmetic number, because the mean of its divisors is an integer number (5155561100004).
Almost surely, 210311122200007 is an apocalyptic number.
10311122200007 is a deficient number, since it is larger than the sum of its proper divisors (1).
10311122200007 is an equidigital number, since it uses as much as digits as its factorization.
10311122200007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 168, while the sum is 20.
Adding to 10311122200007 its reverse (70000222111301), we get a palindrome (80311344311308).
The spelling of 10311122200007 in words is "ten trillion, three hundred eleven billion, one hundred twenty-two million, two hundred thousand, seven".
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