Base | Representation |
---|---|
bin | 11110000000100111111… |
… | …10110101010011101001 |
3 | 10122120112001002122101202 |
4 | 33000103332311103221 |
5 | 113343222102430132 |
6 | 2105405434253545 |
7 | 134332204124336 |
oct | 17002376652351 |
9 | 3576461078352 |
10 | 1031127389417 |
11 | 368331591314 |
12 | 147a0a5872b5 |
13 | 763090b1268 |
14 | 37c9a4bd98d |
15 | 1bc4e336762 |
hex | f013fb54e9 |
1031127389417 has 2 divisors, whose sum is σ = 1031127389418. Its totient is φ = 1031127389416.
The previous prime is 1031127389407. The next prime is 1031127389471. The reversal of 1031127389417 is 7149837211301.
Together with next prime (1031127389471) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 854831534041 + 176295855376 = 924571^2 + 419876^2 .
It is a cyclic number.
It is not a de Polignac number, because 1031127389417 - 28 = 1031127389161 is a prime.
It is not a weakly prime, because it can be changed into another prime (1031127389407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515563694708 + 515563694709.
It is an arithmetic number, because the mean of its divisors is an integer number (515563694709).
Almost surely, 21031127389417 is an apocalyptic number.
It is an amenable number.
1031127389417 is a deficient number, since it is larger than the sum of its proper divisors (1).
1031127389417 is an equidigital number, since it uses as much as digits as its factorization.
1031127389417 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 254016, while the sum is 47.
The spelling of 1031127389417 in words is "one trillion, thirty-one billion, one hundred twenty-seven million, three hundred eighty-nine thousand, four hundred seventeen".
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