Base | Representation |
---|---|
bin | 1001011000001100101010… |
… | …0101011110011101000011 |
3 | 1100111202022122100201211201 |
4 | 2112003022211132131003 |
5 | 2322420041001111344 |
6 | 33532542152122031 |
7 | 2112653062453423 |
oct | 226031245363503 |
9 | 40452278321751 |
10 | 10311320332099 |
11 | 331600856a386 |
12 | 11a64a0396317 |
13 | 59a47937ab97 |
14 | 2790db8c8483 |
15 | 12d34b3694d4 |
hex | 960ca95e743 |
10311320332099 has 2 divisors, whose sum is σ = 10311320332100. Its totient is φ = 10311320332098.
The previous prime is 10311320332097. The next prime is 10311320332123. The reversal of 10311320332099 is 99023302311301.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10311320332099 - 21 = 10311320332097 is a prime.
It is a super-3 number, since 3×103113203320993 (a number of 40 digits) contains 333 as substring.
Together with 10311320332097, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (10311320332097) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5155660166049 + 5155660166050.
It is an arithmetic number, because the mean of its divisors is an integer number (5155660166050).
Almost surely, 210311320332099 is an apocalyptic number.
10311320332099 is a deficient number, since it is larger than the sum of its proper divisors (1).
10311320332099 is an equidigital number, since it uses as much as digits as its factorization.
10311320332099 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 26244, while the sum is 37.
The spelling of 10311320332099 in words is "ten trillion, three hundred eleven billion, three hundred twenty million, three hundred thirty-two thousand, ninety-nine".
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