Base | Representation |
---|---|
bin | 10111011100100110111011… |
… | …110001011111001110011011 |
3 | 111112010021101012021222112222 |
4 | 113130212323301133032123 |
5 | 102004013322122401021 |
6 | 1003153050451254255 |
7 | 30502151003360363 |
oct | 2734467361371633 |
9 | 445107335258488 |
10 | 103121020122011 |
11 | 2a948419554811 |
12 | b695664baa38b |
13 | 45703692c41a8 |
14 | 1b671267199a3 |
15 | bdc6338226ab |
hex | 5dc9bbc5f39b |
103121020122011 has 2 divisors, whose sum is σ = 103121020122012. Its totient is φ = 103121020122010.
The previous prime is 103121020121957. The next prime is 103121020122047. The reversal of 103121020122011 is 110221020121301.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 103121020122011 - 26 = 103121020121947 is a prime.
It is not a weakly prime, because it can be changed into another prime (103121020722011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51560510061005 + 51560510061006.
It is an arithmetic number, because the mean of its divisors is an integer number (51560510061006).
Almost surely, 2103121020122011 is an apocalyptic number.
103121020122011 is a deficient number, since it is larger than the sum of its proper divisors (1).
103121020122011 is an equidigital number, since it uses as much as digits as its factorization.
103121020122011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 103121020122011 its reverse (110221020121301), we get a palindrome (213342040243312).
The spelling of 103121020122011 in words is "one hundred three trillion, one hundred twenty-one billion, twenty million, one hundred twenty-two thousand, eleven".
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