Base | Representation |
---|---|
bin | 10111011100100110111011… |
… | …111000110001010101110011 |
3 | 111112010021101022212222111101 |
4 | 113130212323320301111303 |
5 | 102004013323114444334 |
6 | 1003153051000225231 |
7 | 30502151025531523 |
oct | 2734467370612563 |
9 | 445107338788441 |
10 | 103121022031219 |
11 | 2a94841a639175 |
12 | b69566576b217 |
13 | 45703698121ba |
14 | 1b67126a95683 |
15 | bdc633a9d214 |
hex | 5dc9bbe31573 |
103121022031219 has 2 divisors, whose sum is σ = 103121022031220. Its totient is φ = 103121022031218.
The previous prime is 103121022031217. The next prime is 103121022031271. The reversal of 103121022031219 is 912130220121301.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 103121022031219 - 21 = 103121022031217 is a prime.
It is a super-2 number, since 2×1031210220312192 (a number of 29 digits) contains 22 as substring.
Together with 103121022031217, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (103121022031217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51560511015609 + 51560511015610.
It is an arithmetic number, because the mean of its divisors is an integer number (51560511015610).
Almost surely, 2103121022031219 is an apocalyptic number.
103121022031219 is a deficient number, since it is larger than the sum of its proper divisors (1).
103121022031219 is an equidigital number, since it uses as much as digits as its factorization.
103121022031219 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 28.
The spelling of 103121022031219 in words is "one hundred three trillion, one hundred twenty-one billion, twenty-two million, thirty-one thousand, two hundred nineteen".
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