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1031210313131 is a prime number
BaseRepresentation
bin11110000000110001110…
…11001010010110101011
310122120201211010121100102
433000120323022112223
5113343404320010011
62105421555500015
7134334232015415
oct17003073122653
93576654117312
101031210313131
1136837437a109
12147a322b760b
137632032634b
1437ca75079b5
151bc5676673b
hexf018eca5ab

1031210313131 has 2 divisors, whose sum is σ = 1031210313132. Its totient is φ = 1031210313130.

The previous prime is 1031210313121. The next prime is 1031210313163. The reversal of 1031210313131 is 1313130121301.

1031210313131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1031210313131 - 214 = 1031210296747 is a prime.

It is a super-2 number, since 2×10312103131312 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1031210313121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515605156565 + 515605156566.

It is an arithmetic number, because the mean of its divisors is an integer number (515605156566).

Almost surely, 21031210313131 is an apocalyptic number.

1031210313131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1031210313131 is an equidigital number, since it uses as much as digits as its factorization.

1031210313131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162, while the sum is 20.

Adding to 1031210313131 its reverse (1313130121301), we get a palindrome (2344340434432).

The spelling of 1031210313131 in words is "one trillion, thirty-one billion, two hundred ten million, three hundred thirteen thousand, one hundred thirty-one".