Base | Representation |
---|---|
bin | 11110000000110001110… |
… | …11001010010111001011 |
3 | 10122120201211010121101121 |
4 | 33000120323022113023 |
5 | 113343404320010123 |
6 | 2105421555500111 |
7 | 134334232015462 |
oct | 17003073122713 |
9 | 3576654117347 |
10 | 1031210313163 |
11 | 36837437a138 |
12 | 147a322b7637 |
13 | 76320326374 |
14 | 37ca75079d9 |
15 | 1bc5676675d |
hex | f018eca5cb |
1031210313163 has 2 divisors, whose sum is σ = 1031210313164. Its totient is φ = 1031210313162.
The previous prime is 1031210313131. The next prime is 1031210313169. The reversal of 1031210313163 is 3613130121301.
1031210313163 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1031210313163 - 25 = 1031210313131 is a prime.
It is not a weakly prime, because it can be changed into another prime (1031210313169) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515605156581 + 515605156582.
It is an arithmetic number, because the mean of its divisors is an integer number (515605156582).
Almost surely, 21031210313163 is an apocalyptic number.
1031210313163 is a deficient number, since it is larger than the sum of its proper divisors (1).
1031210313163 is an equidigital number, since it uses as much as digits as its factorization.
1031210313163 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 25.
Adding to 1031210313163 its reverse (3613130121301), we get a palindrome (4644340434464).
The spelling of 1031210313163 in words is "one trillion, thirty-one billion, two hundred ten million, three hundred thirteen thousand, one hundred sixty-three".
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