Base | Representation |
---|---|
bin | 11110000000110010000… |
… | …10110100100101101101 |
3 | 10122120201221220121210212 |
4 | 33000121002310211231 |
5 | 113343410323234013 |
6 | 2105422110512205 |
7 | 134334255050561 |
oct | 17003102644555 |
9 | 3576657817725 |
10 | 1031212321133 |
11 | 368375520815 |
12 | 147a32b05665 |
13 | 7632087a307 |
14 | 37ca78ab6a1 |
15 | 1bc56a116a8 |
hex | f0190b496d |
1031212321133 has 2 divisors, whose sum is σ = 1031212321134. Its totient is φ = 1031212321132.
The previous prime is 1031212321127. The next prime is 1031212321147. The reversal of 1031212321133 is 3311232121301.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1031195568484 + 16752649 = 1015478^2 + 4093^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1031212321133 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1031212321099 and 1031212321108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1031212321333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515606160566 + 515606160567.
It is an arithmetic number, because the mean of its divisors is an integer number (515606160567).
Almost surely, 21031212321133 is an apocalyptic number.
It is an amenable number.
1031212321133 is a deficient number, since it is larger than the sum of its proper divisors (1).
1031212321133 is an equidigital number, since it uses as much as digits as its factorization.
1031212321133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 1031212321133 its reverse (3311232121301), we get a palindrome (4342444442434).
The spelling of 1031212321133 in words is "one trillion, thirty-one billion, two hundred twelve million, three hundred twenty-one thousand, one hundred thirty-three".
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