Base | Representation |
---|---|
bin | 11110000000110010001… |
… | …01100001111100110001 |
3 | 10122120202000020200212021 |
4 | 33000121011201330301 |
5 | 113343411013444332 |
6 | 2105422134031441 |
7 | 134334264066025 |
oct | 17003105417461 |
9 | 3576660220767 |
10 | 1031213031217 |
11 | 368375966266 |
12 | 147a331a8581 |
13 | 76320a68595 |
14 | 37ca7a14385 |
15 | 1bc56b01c97 |
hex | f019161f31 |
1031213031217 has 2 divisors, whose sum is σ = 1031213031218. Its totient is φ = 1031213031216.
The previous prime is 1031213031143. The next prime is 1031213031263. The reversal of 1031213031217 is 7121303121301.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 719992978576 + 311220052641 = 848524^2 + 557871^2 .
It is a cyclic number.
It is not a de Polignac number, because 1031213031217 - 215 = 1031212998449 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1031213031191 and 1031213031200.
It is not a weakly prime, because it can be changed into another prime (1031213031917) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515606515608 + 515606515609.
It is an arithmetic number, because the mean of its divisors is an integer number (515606515609).
Almost surely, 21031213031217 is an apocalyptic number.
It is an amenable number.
1031213031217 is a deficient number, since it is larger than the sum of its proper divisors (1).
1031213031217 is an equidigital number, since it uses as much as digits as its factorization.
1031213031217 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 756, while the sum is 25.
Adding to 1031213031217 its reverse (7121303121301), we get a palindrome (8152516152518).
The spelling of 1031213031217 in words is "one trillion, thirty-one billion, two hundred thirteen million, thirty-one thousand, two hundred seventeen".
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