Base | Representation |
---|---|
bin | 10111011100100111001101… |
… | …000111111100101001111001 |
3 | 111112010022010111001102012121 |
4 | 113130213031013330221321 |
5 | 102004014421133104033 |
6 | 1003153135410441241 |
7 | 30502161136602502 |
oct | 2734471507745171 |
9 | 445108114042177 |
10 | 103121311222393 |
11 | 2a9485588aa842 |
12 | b695726593221 |
13 | 45703b46c7239 |
14 | 1b67153253ba9 |
15 | bdc64e17462d |
hex | 5dc9cd1fca79 |
103121311222393 has 2 divisors, whose sum is σ = 103121311222394. Its totient is φ = 103121311222392.
The previous prime is 103121311222327. The next prime is 103121311222403. The reversal of 103121311222393 is 393222113121301.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 102869961405289 + 251349817104 = 10142483^2 + 501348^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-103121311222393 is a prime.
It is not a weakly prime, because it can be changed into another prime (103121311222693) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51560655611196 + 51560655611197.
It is an arithmetic number, because the mean of its divisors is an integer number (51560655611197).
Almost surely, 2103121311222393 is an apocalyptic number.
It is an amenable number.
103121311222393 is a deficient number, since it is larger than the sum of its proper divisors (1).
103121311222393 is an equidigital number, since it uses as much as digits as its factorization.
103121311222393 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11664, while the sum is 34.
Adding to 103121311222393 its reverse (393222113121301), we get a palindrome (496343424343694).
The spelling of 103121311222393 in words is "one hundred three trillion, one hundred twenty-one billion, three hundred eleven million, two hundred twenty-two thousand, three hundred ninety-three".
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