Base | Representation |
---|---|
bin | 10111011100100111001101… |
… | …000111111100110011011000 |
3 | 111112010022010111001110001002 |
4 | 113130213031013330303120 |
5 | 102004014421133114000 |
6 | 1003153135410444132 |
7 | 30502161136604330 |
oct | 2734471507746330 |
9 | 445108114043032 |
10 | 103121311223000 |
11 | 2a948558900244 |
12 | b695726593648 |
13 | 45703b46c75b5 |
14 | 1b671532540c0 |
15 | bdc64e1748d5 |
hex | 5dc9cd1fccd8 |
103121311223000 has 256 divisors, whose sum is σ = 277388059852800. Its totient is φ = 35149410240000.
The previous prime is 103121311222981. The next prime is 103121311223003. The reversal of 103121311223000 is 322113121301.
It is a happy number.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (103121311223003) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 2284910435 + ... + 2284955565.
It is an arithmetic number, because the mean of its divisors is an integer number (1083547108800).
Almost surely, 2103121311223000 is an apocalyptic number.
103121311223000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 103121311223000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (138694029926400).
103121311223000 is an abundant number, since it is smaller than the sum of its proper divisors (174266748629800).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
103121311223000 is a wasteful number, since it uses less digits than its factorization.
103121311223000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 47059 (or 47045 counting only the distinct ones).
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 103121311223000 its reverse (322113121301), we get a palindrome (103443424344301).
The spelling of 103121311223000 in words is "one hundred three trillion, one hundred twenty-one billion, three hundred eleven million, two hundred twenty-three thousand".
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