Base | Representation |
---|---|
bin | 11110000000110010010… |
… | …10011000001101001111 |
3 | 10122120202002122021002110 |
4 | 33000121022120031033 |
5 | 113343411330131111 |
6 | 2105422221155103 |
7 | 134334310641024 |
oct | 17003112301517 |
9 | 3576662567073 |
10 | 1031214302031 |
11 | 368376654021 |
12 | 147a336bba93 |
13 | 763210c1b44 |
14 | 37ca7c6554b |
15 | 1bc56ca35a6 |
hex | f01929834f |
1031214302031 has 32 divisors (see below), whose sum is σ = 1483085260800. Its totient is φ = 635366665440.
The previous prime is 1031214302009. The next prime is 1031214302033. The reversal of 1031214302031 is 1302034121301.
It is not a de Polignac number, because 1031214302031 - 26 = 1031214301967 is a prime.
It is a super-2 number, since 2×10312143020312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1031214301989 and 1031214302007.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1031214302033) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 729811 + ... + 1610916.
It is an arithmetic number, because the mean of its divisors is an integer number (46346414400).
Almost surely, 21031214302031 is an apocalyptic number.
1031214302031 is a deficient number, since it is larger than the sum of its proper divisors (451870958769).
1031214302031 is a wasteful number, since it uses less digits than its factorization.
1031214302031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2340939.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 1031214302031 its reverse (1302034121301), we get a palindrome (2333248423332).
The spelling of 1031214302031 in words is "one trillion, thirty-one billion, two hundred fourteen million, three hundred two thousand, thirty-one".
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