Base | Representation |
---|---|
bin | 110000000001010001… |
… | …1001101101100111111 |
3 | 100212011202020102002101 |
4 | 1200002203031230333 |
5 | 3142143213010303 |
6 | 115212410205531 |
7 | 10310313354241 |
oct | 1400243155477 |
9 | 325152212071 |
10 | 103122000703 |
11 | 3a808754477 |
12 | 17b9b4238a7 |
13 | 995556b737 |
14 | 4dc3944091 |
15 | 2a3837bd1d |
hex | 18028cdb3f |
103122000703 has 2 divisors, whose sum is σ = 103122000704. Its totient is φ = 103122000702.
The previous prime is 103122000649. The next prime is 103122000749. The reversal of 103122000703 is 307000221301.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 103122000703 - 225 = 103088446271 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (103122000763) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51561000351 + 51561000352.
It is an arithmetic number, because the mean of its divisors is an integer number (51561000352).
Almost surely, 2103122000703 is an apocalyptic number.
103122000703 is a deficient number, since it is larger than the sum of its proper divisors (1).
103122000703 is an equidigital number, since it uses as much as digits as its factorization.
103122000703 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 252, while the sum is 19.
It can be divided in two parts, 10312 and 2000703, that added together give a triangular number (2011015 = T2005).
The spelling of 103122000703 in words is "one hundred three billion, one hundred twenty-two million, seven hundred three", and thus it is an aban number.
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