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1031220315313 is a prime number
BaseRepresentation
bin11110000000110011000…
…01010100010010110001
310122120202111221202202121
433000121201110102301
5113343414400042223
62105422554114241
7134334413024326
oct17003141242261
93576674852677
101031220315313
11368379a90981
12147a3571b981
1376322418bb6
1437ca898cb4d
151bc5759015d
hexf0198544b1

1031220315313 has 2 divisors, whose sum is σ = 1031220315314. Its totient is φ = 1031220315312.

The previous prime is 1031220315277. The next prime is 1031220315319. The reversal of 1031220315313 is 3135130221301.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 579216889969 + 452003425344 = 761063^2 + 672312^2 .

It is a cyclic number.

It is not a de Polignac number, because 1031220315313 - 233 = 1022630380721 is a prime.

It is not a weakly prime, because it can be changed into another prime (1031220315319) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 515610157656 + 515610157657.

It is an arithmetic number, because the mean of its divisors is an integer number (515610157657).

Almost surely, 21031220315313 is an apocalyptic number.

It is an amenable number.

1031220315313 is a deficient number, since it is larger than the sum of its proper divisors (1).

1031220315313 is an equidigital number, since it uses as much as digits as its factorization.

1031220315313 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1620, while the sum is 25.

Adding to 1031220315313 its reverse (3135130221301), we get a palindrome (4166350536614).

The spelling of 1031220315313 in words is "one trillion, thirty-one billion, two hundred twenty million, three hundred fifteen thousand, three hundred thirteen".