Base | Representation |
---|---|
bin | 1001011000001111111100… |
… | …1101011110011101101011 |
3 | 1100111211121011200202100221 |
4 | 2112003333031132131223 |
5 | 2322423343011430011 |
6 | 33533205531510511 |
7 | 2113014003135052 |
oct | 226037715363553 |
9 | 40454534622327 |
10 | 10312203233131 |
11 | 3316420982a58 |
12 | 11a66a7bb8437 |
13 | 59a58a268727 |
14 | 279182c73399 |
15 | 12d39db19971 |
hex | 960ff35e76b |
10312203233131 has 2 divisors, whose sum is σ = 10312203233132. Its totient is φ = 10312203233130.
The previous prime is 10312203233071. The next prime is 10312203233141. The reversal of 10312203233131 is 13133230221301.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10312203233131 - 29 = 10312203232619 is a prime.
It is a super-2 number, since 2×103122032331312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10312203233096 and 10312203233105.
It is not a weakly prime, because it can be changed into another prime (10312203233141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5156101616565 + 5156101616566.
It is an arithmetic number, because the mean of its divisors is an integer number (5156101616566).
Almost surely, 210312203233131 is an apocalyptic number.
10312203233131 is a deficient number, since it is larger than the sum of its proper divisors (1).
10312203233131 is an equidigital number, since it uses as much as digits as its factorization.
10312203233131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 10312203233131 its reverse (13133230221301), we get a palindrome (23445433454432).
The spelling of 10312203233131 in words is "ten trillion, three hundred twelve billion, two hundred three million, two hundred thirty-three thousand, one hundred thirty-one".
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